Two ships are in battle. They fly under the blue and red flags respectively. If the blue ship hasn't already been hit, it has a 0.75 probability of hitting the red flag ship .If the blue flag ship has been hit, it will always miss. If the red flag ship hasn't already been hit it has a 0.25 probability of hitting the blue flag ship. If the red flag ship has been hit it will always miss If the blue flag and red flag ships each shoot at once and the red flag ship shoots first, what is the probability that both ships hit their opposition’s ship? Give your answer to two decimal places

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: