Belinda is jumping on a trampoline. She jumps up with an initial velocity (v0) of 17 feet per second. The function d(t) = v0t-16t^2 gives the height in feet of belinda above the trampoline as a function of time in seconds after her jump. How long after her jump will it take her to return to the trampoline again

1.0625 seconds

Step-by-step explanation:

Given that:

Initial velocity of Belinda,

Height in feet of Belinda above the trampoline is given as the formula:

Where is the time in seconds.

To find:

Time taken by Belinda to come back to trampoline = ?

Solution:

When Belinda will come back to trampoline, the height will be zero.

Putting

We have the equation as:

Therefore, the answer is: 1.0625 seconds

$450

step-by-step explanation:

first, you have to multiply 150x2=300

next, you have to add 150+300= 450

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068