An arrow is shot vertically upward from a platform 35 ft high at a rate of 166 ft/sec. When will the arrow hit the ground? Ignore the air resistance. Use the formula ℎ = −16 2 + 0 + ℎ0. Round your answer to the nearest tenth.

The arrow will hit the ground approximately 10.5 seconds after launch.

Step-by-step explanation:

The arrow experiments a free fall motion, which is a particular form of uniform accelerated motion due to gravity and in which air friction and effects from Earth's rotation can be neglected. Then, the height as a function of time (), measured in feet, is obtained by the following kinematic formula:

(1)

Where:

- Initial height of the arrow, measured in feet.

- Initial velocity of the arrow, measured in feet per second.

- Time, measured in seconds.

- Gravitational acceleration, measured in feet per square second.

If we know that , , and , then the following polynomial is obtained:

(2)

Lastly, we find the roots of the given expression by the Quadratic Formula:

and

Time is a positive variable and then we conclude that the only solution that is physically reasonable is approximately 10.526 seconds.

The arrow will hit the ground approximately 10.5 seconds after launch.

the answer would be c:   ax + b = ax + c

step-by-step explanation: