A car leaving a stop sign accelerates constantly from a speed of 0 feet per second to reach a speed of 44 feet per second. The distance of the car from the stop sign, d d , in feet, at time t t , in seconds, can be found using the equation d=1.1t2 d = 1 . 1 t 2 . What is the average speed of the car, in feet per second, between t=2 t = 2 and t=5 t = 5 ?

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Step-by-step explanation:

The distance of the car from the stop sign, d , in feet, at time t , in seconds, can be found using the equation

The average rate of change of a function f(x) on [a,b] is

We need to find the average speed of the car, in feet per second, between t=2 and t=5.

At t=2,

At t=5,

The average speed of the car, in feet per second, between t=2 and t=5 is

The average speed of the car, in feet per second, between t=2 and t=5 is 7.7 feet per second.

its 4 because 2 times 2 is 4, if you double the number two you get four