Marcus has been running a beverage cart on weekends at the beach, selling water and soda. Last Saturday, he sold 40 bottles of water and 25 sodas, bringing in $110. Sunday, he sold 50 bottles of water and 45 sodas, making $165. What are the prices for each beverage option?

$2 for soda and $1.5 for a bottle of water

Step-by-step explanation:

You start by turning both situations into an equation

Let x represent bottles of water and y represent sodas

Saturday:

Sunday:

You then want to start by cancelling out the x in this equation, to do that you want 40x to become -50x so you:

50÷40=1.25

You then times the whole equation by -1.25

40x+25y=110

×-1.25

-50x+-31.25y= -137.5

You then add this equation by Sunday's equation

50x+45y=165

-50x+-31.25y=-137.5

          13.75y=27.5

You now want to make the co-efficient of y a whole number (for example 15) so you divide 15/13.75=1.09 recurring

13.75y=27.5

×1.09 recurring

    15y=30

15y/15=30/15

     y=2

Now that we know y = 2

We can use either Saturday or Sunday's equation to figure out the value of

Let's use Sunday's:

50x+45×2=165

50x+90=165

50x+90-90=165-90

50x/50=75/50

x=1.5

Let's check our answer with Saturday's equation

40×1.5+25×2=110

This equation is correct

Therefore the prices for each beverage option is $1.5 for a bottle of water and $2 for a soda

the answer to the question is a

step-by-step explanation:

it has the same slope and the same y-intercept.

y + 11 = -7/9(x - 18)

y + 11 =-7/9x + 14

b

y = -7/9x + 3

y-intercept (0, 3)

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.