Which could you use to prove triangle AED is congruent to triangle CEB?

Option (C)

Step-by-step explanation:

Given:

In right triangles ΔAED and CEB,

m∠AED = m∠CEB = 90°

DE ≅ BE

AD ≅ BC

To prove:

ΔAED ≅ ΔCEB

                    Statements                         Reasons

1). m∠AED = m∠BC = 90°              1). Given

2). DE = BE                                     2). Given

3). AD = BC                                    3). Given

4). ΔAED ≅ ΔCEB                          4). By HL theorem of congruence

Option (C) is the answer.

it is a. 4.2 because 7.6-3.4 gets the remaining length of 4.2. i might be wrong but i am pretty sure this is the answer.

2nd one in the first row is correct