Consider a triangle with two sides that measure 7 cm and 11 cm forming an angle
that measures 100°.

Find the length of the third side to the nearest centimeter
A) 12 cm
B) 13 cm
C) 14 cm
D) 15 cm

9514 1404 393

  C)  14 cm

Step-by-step explanation:

A triangle solver can quickly show you the third side is 14 cm.

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The law of cosines can be used for this purpose. If the given sides are 'a' and 'b', and the third side is 'c', then that law tells you ...

  c² = a² +b² -2ab·cos(C)

  c² = 7² +11² -2·7·11·cos(100°) ≈ 196.74

  c ≈ √196.74 ≈ 14.03

The length of the third side is about 14 cm.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

where is the diagram? shown below where? ?

step-by-step explanation: