A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find out the time at which the rocket will reach its max, to the nearest 100th of a second. y=−16x 2 +193x+128

Let x be -b/2a

x = -193/2•(-16)

x = -193/-32

x = 6.03125

Now, plug this value of x into every x in the function and simplify. The max is the y value.

Can you finish?

2

step-by-step explanation:

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7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐