A random sample of 2,000 driver's license applications found that 17% reported their eye color as blue. What is the margin of error for the sample? Round to the nearest tenth of a percent.

1.646%

Step-by-step explanation:

Sample size (n) = 2000

Sample Proportion p = 17% = 0.17

α = 0.95

Margin of Error :

Z(1-α)/2 * √((p*(1 - p)) /n)

Z(1 - 0.95/2) * √((0.17 * (1 - 0.17) / 2000)

Zscore = 1.96

1.96 * √(0.1411/2000)

1.96 * √0.00007055

1.96 * 0.0083994

Hence,

1.96 * 0.0083994

= 0.0164628

= 0.0164628 * 100%

= 1.646%

answer: 2x + 2 − 2 = 10 − 2; subtraction property of equality

step-by-step explanation:

3

step-by-step explanation:

in standard form:

a= dictionaries

b= maps

you have to buy 3 dictionaries, so put a 3 next to the a (dictionaries) so that you can multiply them by each other.

a3+b= 60 (the amount of money you have)

we already know the cost of a=15 so replace a with $15

($15 x 3)+b=60

multiply 15 and 3 to get $45 and replace it with $45

45+b=60

and then replace b with 15 to get the total:

45+15=60

that means you have $15 left after buying 3 dictionaries.

15 divided by the cost of a map ($5) equals 3.

so you can buy 3 maps.

sorry if it was confusing!