Two hockey pucks, each with a mass of 0.1 kg, slide across the ice and collide. Before the collision, puck 1 is moving 13 m/s to the east and puck 2 is moving 18 m/s to the west. After the collision, puck 1 is moving at 18 m. s to the west. What is the velocity of puck 2?

1 1/5

step-by-step explanation:

attachment?

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3