Mathematics, 21.11.2020 20:10 mirandac6775

QUICK AND PLEASE DON'T USE SIN CON OR TAN IN YOUR PROOF! AB of △ABC splits AB so that AP:BP=1:3. If M is a midpoint of
CP , then ratio of area of △BPM to the area of △ABC is:
(A) 1/4 (B) 5/8 (C) 3/8

Answers: 2

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QUICK AND PLEASE DON'T USE SIN CON OR TAN IN YOUR PROOF! AB of △ABC splits AB so that AP:BP=1:3. If...

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QUICK AND PLEASE DON'T USE SIN CON OR TAN IN YOUR PROOF! AB of △ABC splits AB so that AP:BP=1:3. If M is a midpoint of CP , then ratio of area of △BPM to the area of △ABC is: (A) 1/4 (B) 5/8 (C) 3/8

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QUICK AND PLEASE DON'T USE SIN CON OR TAN IN YOUR PROOF! AB of △ABC splits AB so that AP:BP=1:3. If M is a midpoint of
CP , then ratio of area of △BPM to the area of △ABC is:
(A) 1/4 (B) 5/8 (C) 3/8