What is the directrix of the parabola? (y+4)2=4(x−2)

x=1

Step-by-step explanation:

for y²=4ax

directrix is x=-a

for y²=4x ,directrix is x=-1

for y²=4(x-2), shift directrix 2 units right.

so directrix is x=-1+2=1

so for (y+4)²=4(x-2) directrix is x=1

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this