Rahul has a farm he wishes to fence. The farm is the pentagon ABCDE, shown below. He knows that ABCD is a 140 m by 150 m rectangle, as shown below. He also knows that E is 50 m from the side AB and 30 m from the side BC. Determine the length of AE, the length of DE, and the perimeter of pentagon ABCDE

The diagram of the pentagon is missing, so i have attached it.

|AE| = 130 m

|DE| = 150 m

Perimeter of pentagon = 720 m

Step-by-step explanation:

From the diagram, we can find AE from pythagoras theorem;

|AE| = √(|AA'|² + 50²)

Where AA' is the length from A to the perpendicular angle.

Now, AB = 150, and A'B is parallel to 30 m. Thus, A'B = 30

AA' = AB - A'B = 150 - 30

AA' = 120

Thus;

|AE| = √(120² + 50²)

|AE| = √(14400 + 2500)

|AE| = √16900

|AE| = 130

Similarly,

|DE| = √(|DD'|² + |ED'|²)

ED' = BC - 50

ED' = 140 - 50

ED' = 90

Also, DD' is parallel to AA' and is = 120

Thus;

|DE| = √(120² + 90²)

|DE| = √22500

|DE| = 150

Perimeter of pentagon = 150 + 130 + 150 + 150 + 140 = 720

b

step-by-step explanation:

a difference is the result of subtraction. while each of these expressions has subtraction in it, a difference will be the result when subtraction is the last operation applied in the order of operations for the expression. this means subtraction must be outside of the parenthesis. only b has this.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet