Write an equation in slope intercept form that passes through the points (-4,3) and (0,2)

Step-by-step explanation:

Slope-intercept form: y = mx + b

Slope formula:

Given points: (-4, 3), (0, 2)

(0, 2) = (x1, y1)

(-4, 3) = (x2, y2)

To write the equation in slope-intercept form, we need to find the slope(m) and the y-intercept(b) of the equation.

First, let's find the slope. To do this, input the given points into the formula used to find slope:

Simplify:

3 - 2 = 1

-4 - 0 = -4

The slope is .

To find the y-intercept, input the slope and one of the given points(in this example I'll use point (0, 2)) into the equation and solve for b:

2 = 0 + b

2 = b

The y-intercept is 2.

Now that we know the slope and the y-intercept, we can write the equation:

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

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step-by-step explanation: