Question 1 (1 point) Find the value of f(2), wheref|x
nd{
4x + 1, x < 1
7. x = 1
(2 – 3x², x > 1
O-4
0-10
O2
0-34
07

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Step-by-step explanation:

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squares, rhombus, rectangles

38.6°

step-by-step explanation:

resultant is 10 pound

smaller force = 8 pound

angle formed = tan⁻¹(

                        =tan⁻¹(

                          =tan⁻¹(0.8)

                        =38.6°