I NEED HELP PLEASE ANSWER Multiple Choice:
- Rationalize the denominator
- Convert the bottom of the LHS using an identity
- Factor the RHS
- Convert tan^2(theta) + 1 of the RHS using an identity
- Find common denominators for RHS
- Cancel the 1s on LHS

(1+cos(theta))/(1-sin^2(theta))=sec(theta)+tan^2(theta)+1

(1+cos(theta))/cos^2(theta)=sec(theta)+sec^2(theta)-1+1

(1-cos(theta))/cos^2(theta)=1/cos(theta)+1/cos^2(theta)

1-cos(theta)=cos(theta)+1

2cos(theta)=0

cos(theta)=0

theta=pi/2 and 3pi/2

I don't fully understand your question but it's quite easy to solve. As shown above, option (2) is good and you can factor the RHS but I would find it rather trivial when you can multiply both sides by cos^2(theta) just as easily. I hope this helps you.

the answer is 5636.7

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it