The 12 girls at Suzie’s volleyball camp have decided to wear their camp ID’s on loops of string around their necks. If each girl needs 1 2 yard of string, how much string do they need in all? Suzie did this work to solve the problem: 12 1 ÷ 1 2 = 12 1 × 2 1 = 24 1 = 24 yards of string Did Suzie solve the problem correctly? No. She should have multiplied 12 and One-half to solve. No. She did not multiply the numerators correctly. No. She did not simplify 24 Over 1 correctly. Yes. Her work is correct.

think about it deeply and passionately about this property

i am sorry

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)

sample answer: you can determine whether each element of the domain is paired with exactly one element of the range. for example, if given a graph, you could use the vertical line test; if a vertical line intersects the graph more than once, then the relation that the graph represents is not a function.

1260=3*6*7*10=3^2*2^2*7*5 perfect cude = 3^3*2^

step-by-step explanation: