Two hot air balloons are traveling along the same path away from a town, beginning from different locations at the same time. Henry's balloon begins
30 miles from the town and is 48 miles from the town after 2 hours. The
distance of Tasha's balloon from the town is represented by the function y =
8x+ 20.
Whích balloon was farther from the town at the beginning, and which traveled
more quickly?
O
A. Tasha's balloon was farther from the town at the beginning, but
Henry's balloon traveled more quickly.
O
B. Tasha's balloon was farther from the town at the beginning, and it
traveled more quickly.
O
C. Henry's balloon was farther from the town at the beginning, but
Tasha's balloon traveled more quickly.
O
D. Henry's balloon was farther from the town at the beginning, and it
traveled more quickly.

Henry's balloon was farther from the town at the beginning and Henry's balloon traveled more quickly.

Step-by-step explanation:

The distance of Tasha's balloon from the town is represented by the function y = 8x+ 20 (1)

Where y is the distance in miles from the town and x represents the time of fly in hours.

So, at the start of the journey i.e. at x = 0, y = 20 miles {From equation (1)} from the town.

Again, Tasha's balloon is traveling at a rate of 8 miles per hour.

Now, Henry's balloon begins 30 miles from the town and is 48 miles from the town after 2 hours.

So, Henry's balloon traveling with the speed of  miles per hour.

Therefore, Henry's balloon was farther from the town at the beginning i.e. 30 miles from the town. And Henry's balloon traveled more quickly i.e at the rate of 9 miles per hour. (Answer)

the answer is two. hope this !

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)