Which must be larger log 15 Or In 15? And why

ln 15 must be greater (larger than) if log 15 is common.

Step-by-step explanation:

log 15 [assumed to be a common logarithm]

‹–› 15 = 10 ^ log(15)

ln 15 [natural log which has a base of e] ‹–› 15 = e ^ ln(15).

10 > e

e ≈ 2.7218.

e is approximately 3 rounded to the nearest whole number.

Logically you would need to raise 3 to a greater power for 3ⁿ = 15. Than 10ⁿ = 15.

For example 3² < 10² → 3³ < 10³ → 3⁴ < 10⁴ → ... Thus 3ⁿ < 10ⁿ for n > 0.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2