The top of a 16-ounce can of a drink is three times thicker than the sides and bottom (SO that the flip-top opener will work properly), and the can has a volume of 473 cubic
centimeters. What should the radius and height of the can be in order to use the least
possible amount of metal? [ Assume that the entire can is made from a single sheet of
#metal, with three layers being used for the top.]
A) r = 3 cm; h = 16.73 cm
B)=3.5 cm; h = 12.29 cm
C)=3.35 cm; h = 13.41 cm
D)= 4.35 cm; h = 14.41 cm
E)= 6.7 cm; h= 3.35 cm

really really sorry if i'm

-12 -5(x + 4) = 3x

-12 - 5x - 20 = 3x

-12 - 20 - 5x = 3x

-32 - 5x = 3x

    + 5x   + 5x

-32 = 8x

8         8

- 4= x

i have no idea just need points sorry

step-by-step explanation:

46

step-by-step explanation:

given

height = 168 cm

formula

height =2.47*f+54.13

solution

168 = 2.47f + 54.13             subtract 54.13 from both sides

168 - 54.13   = 2.47f             combine

113.87 = 2.47f                     divide by 2.47

113.87 / 2.47 = f                   combine

46.1 = f  

answer: 46 cm