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If the radius of this Ferris wheel is 125 feet and the angle between each seat is 36°,
then what is the height of the Ferris wheel seat at point B if the bottom of the wheel is
20 feet off the ground? (Round to the nearest tenth)

The height of the seat at point B above the ground is approximately 218.5 feet

Step-by-step explanation:

The given parameters are;

The radius of the Ferris wheel, r = 125 feet

The angle between each seat, θ = 36°

The height of the Ferris wheel above the ground = 20 feet

Therefore, we have;

The height of the midline, D = The height of the Ferris wheel above the ground + The radius of the Ferris wheel

∴ The height of the midline = 20 feet + 125 feet = 145 feet

The height of the seat at point B above the ground, h = r × sin(θ) + D

By substitution, we have;

h = 125 × sin(36°) + 145 ≈ 218.5 (The answer is rounded to the nearest tenth)

The height of the seat at point B above the ground, h ≈ 218.5 feet.

5+2x=a

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the radius is 2 times the diameter.

step-by-step explanation: