The m<1=4x-30 and the m<5=2x+50. Find m<1 and m<7. A. M<1=130 and M<7=130
B. M<1=130 and M<7=50
C. M<1=50 and M<7=50
D. M<1=50 and M<7=130

D) m<1 = 50 m<7 = 130

Step-by-step explanation:

Lets set up the equation!

We know m<4 is 4x-30 and the m<5 is 2x + 50 due to alternate interior angles they are congruent so we can forge an equation, all we do is set them equal to each other!

4x-30 = 2x+50

Add 30 to both sides

4x = 2x +80

Subtract 2x from both sides.

2x = 80

Divide both sides by 2

x = 40

Now that we know x we can just plug it into the expression of m<4 to find m<1

4x-30

4(40)-30

80 - 30

50

m<4 = 50

Because m<1 and m<4 are vertical angles they are congruent!

m<1 = 50

We also know m<4 and m<5 are congruent so m<5 = 50 as well.

Because <7 is supplementary to <5 we know that the sum of both angles amount to 180.

x represents m<7

50 + x = 180

Now we solve by subtraction 50 from both sides

x = 130

m<7 = 130

Brainliest is appreciated!