a long steel beam has a length of twenty-five meters on a cold day when the temperature is 0*c. what is the length of the beam on a hot day when t

Complete question is;

A long steel beam has a length of twenty-five meters on a coldday when the temperature is 0°C. What is the length of the beam on a hot day when T = 40°C. (α_steel = 1.1 × 10^(-5) °/C)

a. 25.00044 m

b. 25.0044 m

c. 25.011 m

d. 25.044m

e. 25.11 m

Option C: 25.011 m

Step-by-step explanation:

We are given;

Initial Temperature; T1 = 0°C

Final Temperature; T2 = 40°C

Coefficient of linear expansion of steel; α_steel = 1.1 × 10^(-5) °/C

Initial length; L_o = 25 m

We know that formula for change in length is;

ΔL = LαΔT

Plugging in the relevant values, we have;

ΔL = 25 × 1.1 × 10^(-5) × (40 - 0)

ΔL = 0.011 m

Thus, new length is;

L1 = L_o + ΔL

L1 = 25 + 0.011

L1 = 25.011

25

step-by-step explanation:

answer: the answer is (b) amie should have multiplied

step-by-step explanation: given a sphere and a cylinder with same radius and height.

let, 'r' be the radius of the cylinder and sphere and 'h' be the height of the cylinder. according to the question,

r = h.

now, the volume of the sphere will be

and the volume of the cylinder will be

therefore, we have

thus, ammie should have multiplied the volume of the sphere