What is the sum of 4 - 7i and the conjugate of 2 + 3i ? A.6 - 4i
B.8 - 21i
C.8 - 4i
D.6 - 10i

The conjugate of a complex number z = a + b i is z * = a - b i. So

(4 - 7i ) + (2 + 3i )* = (4 - 7i ) + (2 - 3i )

… = (4 + 2) + (-7i - 3i)

… = 6 - 10i

and the answer is D.

practice. practice. practice.

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead