The height after t seconds of an object projected upward with an initial velocity of 48 feet per second from a 210-foot tower is modeled by the functionh\left(t\right)=-16t^2+48t+ 210h(t)=−16t 2 +48t+210. When will the object be 50 feet high?

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."

what? that isnt a question

step-by-step explanation:

step-by-step explanation: