Two stores have movies to rent. The first store charges a $20 per-month membership fee plus $1.50 per movie rented.
The second store has no membership fee but charges $3.50 per movie rented.
How many movies would you have to rent in order for the cost to be the same at both stores?

yes the data was not prsented

step-by-step explanation:

add a pic of the graph, then ill edit this "answer" and solve it for you : 3

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.