For the current year come up with rules to convert a given date into a day of the week for both the ordinal and international fixed calendars. Then if someone told you that thier birthday was on a Thursday could you come up with a rule to figure out his birthday? Why or Why not? Thier is 3 questions pls answer them all and pls explain because I don't understand at all.

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Step-by-step explanation:

a) Ordinal Calendar

The ordinal calendar numbers days of the year sequentially, so any given date is specified only by its day number: 1 to 366. In 2020, Jan 1 was a Wednesday, so the rule needs to be ...

  day of week = ((ordinal date) +3) mod 7

This will give a result from 0 to 6. Those numbers map to days of the week as follows:

  0: Saturday; 1: Sunday; 2: Monday; 3: Tuesday; 4: Wednesday; 5: Thursday; 6: Friday

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b) International Fixed Calendar

The international fixed calendar has 13 months of 28 days. The first day of the year is always Sunday, so the day of the week is ...

  day of week = (International Fixed Calendar date) mod 7

In 2020, there are two "leap days" that have day number 29. Days numbered 29 have no associated day of the week.

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c) There is no rule that maps weekday to day of the year. (Each weekday is repeated many times (52 or 53) through the year, so there can be no functional relationship.)

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet