The perimeter of a triangle is 59 cm. The first side is 7 cm shorter than the second side. The third side is 4 cm less than twice the length of the first side. Find length of each side

Given:

The perimeter of a triangle is 59 cm.

The first side is 7 cm shorter than the second side.

The third side is 4 cm less than twice the length of the first side.

To find:

The length of each side.

Solution:

Let x be the second side.

Then, according to the question,

First side = x-7

Third side = 2(x-7)-4

Perimeter of a triangle is the sum of all of its sides.

Add 25 on both sides.

Divide both sides by 4.

Now,

First sides =21 - 7=14 cm

Second side = 21 cm

Third side = 2(14)-4 = 24 cm

Therefore, the three sides of triangle are 14 cm, 21 cm and 24 cm respectively.

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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