The perimeter of a triangular garden is 72 feet. Find the length of the three sides if the middle length side is 4 feet greater than twice the length of the smallest side, and the longest side is 4 feet less than 3 times the length of the smallest side

Smallest length side = 12 ft

Middle length side = 28 ft

Longest length side = 32 ft

Step-by-step explanation:

Perimeter of ∆ = sum of all its length sides

Thus, we are given that:

Perimeter = 72 ft

Let x represent the smallest length side. Therefore:

Smallest length side = x ft

Middle length side = (2x + 4) ft

Longest length side = (3x - 4) ft

Thus:

(2x + 4) + (3x - 4) + x = 72

Solve for x

2x + 4 + 3x - 4 + x = 72

Collect like terms

2x + 3x + x + 4 - 4 = 72

6x = 72

Divide both sides by 6

x = 72/6

x = 12

Find the length of all 3 sides by plugging in the value of x in each expression:

Smallest length side = x ft = 12 ft

Middle length side = (2x + 4) ft = (2(12) + 4) = 24 + 4 = 28 ft

Longest length side = (3x - 4) ft = (3(12) - 4) = (36 - 4) = 32 ft

25% is the answer