A game of chance is played using a six-sided die. If a 1,2 or 3 is rolled the player wins $0 if a 4 or 5 is rolled the player wins $7. If a 6 is rolled the player wins $10. If each play of the game costs 5$ what is the expected pay off?

-2.50

Step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

the answer is 13

step-by-step explanation:

5*5=25

12*12=144

25+144=169

169^2=13