Find the exact values of the six trigonometric functions of 0

Complete question is;

Find the exact values of the six trigonometric functions 0 if the terminal side of 0 in standard position contains the points(-5,-4).

Sin θ = -4/√41

Cos θ = -5/√41

tan θ = 4/5

Cosec θ = (√41)/-4

Sec θ = (√41)/-5

Cot θ = 5/4

Step-by-step explanation:

Now, we are given the point (-5, -4)

These are x and y points.

They will form a triangle and we know that from pythagoras theorem;

x² + y² = r²

Where r is the distance between the point and the origin

Thus;

r² = (-5)² + (-4)²

r² = 25 + 16

r = √41

So, y is the opposite side of the triangle while x is the adjacent side with r being the hypotenuse.

Thus, the trigonometric ratios are;

Sin θ = opp/hyp = -4/√41

Cos θ = adj/hyp = -5/√41

tan θ = opp/adj = -4/-5 = 4/5

Cosec θ = 1/Sin θ = 1/(-4/√41) = (√41)/-4

Sec θ = 1/cos θ = 1/(-5/√41) = (√41)/-5

Cot θ = 1/tan θ = 1/(4/5) = 5/4

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step-by-step explanation: