The number of passengers in the bus double every minute. The bus was full of passengers at 7.45am. When was it one quarter full?

Knowing how the bus fills, we want to find the time where the bus is one-quarter full.

The bus is one-quarter full at 7:43 am.

We know that at 7:45 am the bus is full. Let's say that the full bus has N people inside.

Each minute the population doubles, so if we go backwards, each minute the population is divided by 2.

One minute before, the bus must have half of the above population, meaning that at 7:44 am, the bus has N/2 people.

Another minuter before the people inside is halved again, then at 7:43 am we will have (N/2)/2 = N/4 people.

And if N is the people in a full bus, then N/4 represents the buss a quarter full.

Then we can answer the question as:

The bus is one-quarter full at 7:43 am.

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7:43 am.

Step-by-step explanation:

it was  1/2 full one minute ago then another 1/2 = 1/4 full 2 minutes ago.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2