La suma de tres números enteros impares consecutivos es 45 ¿cuales son los números?

13, 15, 17

Consider three consecutive odd integers (2n−1),(2n+1),(2n+3)
Where n is Integer?

If the sum of these odd integers is 45, 
Then: (2n−1)+(2n+1)+(2n+3)=45
6n+3=45
6n=42
n=7

Substituting n=7 into (2n−1),(2n+1),(2n+3)
Gives 13, 15, 17

To check: 13+15+17=45

18.36. give me brainliest!

step-by-step explanation:

you have to multiply 1.53 by 12 so the equation is 12x1.53 and then that is your answer.