A new Youth Sports Center is being built in Pagosa Springs. The perimeter of the rectangular playing field is 236 yards. The length of the field is 2 yards less than double the width. What are the dimensions of the playing field?

The width is yards

The length is yards.

Width = 40 yards ; length = 78 yards

Step-by-step explanation:

Recall :

Perimeter of rectangle : 2 (length + Width)

Given that :

Perimeter = 236 yards

Let length = l ; width = w

Length = (2w) - 2

Hence ;

236 = 2[(2w - 2) + w]

236 = 2(2w - 2 + w)

236 = 2(3w - 2)

236 = 6w - 4

236 + 4 = 6w

240 = 6w

w = 240/6

w = 40 yards

Length = 2(40) - 2 = 80 - 2 = 78 yards

answer:

step-by-step explanation:

hi there!

the answer will be d: 2