How do you do these two questions?

y(t) → 2 as t → ∞

dP/dt = P (P/1850 − 1) (1 − P/16000)

Step-by-step explanation:

The graph shows how dy/dt changes as a function of y.

At t = 0, y = -0.5.

At y = -0.5, dy/dt > 0.  Therefore, y is increasing.

y continues to increases until y = 2.  At this point, dy/dt = 0, and changes signs from positive to negative, so y begins to decrease.  dy/dt then becomes positive again, and the cycle repeats.

So y approaches 2 as t approaches infinity.

dP/dt is negative when P < 1850.

dP/dt is positive when 1850 < P < 16,000.

dP/dt is negative when P > 16,000.

dP/dt is 0 when P is 0.

Therefore, dP/dt = P (P/1850 − 1) (1 − P/16000).

sine

step-by-step explanation: