5. What is the equation of a line that is perpendicular to -x + 2y = 4 and passes through the point (-2,1)? a.
Write the equation -x + 2y = 4 in slope-intercept form
b. Identify the slope of the line represented in part a.
C.
What is the slope of the line perpendicular to the line in steps a and b?
d. Write the equation of the perpendicular line in slope-intercept form.

Please check the explanation.

Step-by-step explanation:

Given the equation

a) writing the equation in the slope-intercept form

We know that the slope-intercept form of the equation of the line is

where m is the slope of the line

so writing the equation in the slope-intercept form

b) Identify the slope of the line represented in part a

As the equation in slope-intercept form is

Here,

m = slope = 1/2     ∵

c) What is the slope of the line perpendicular to the line in steps a and b

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line, so

As the slope = 1/2

So the slope of the perpendicular line will be: -2

d. Write the equation of the perpendicular line in slope-intercept form.

Therefore, the point-slope form of the equation of the perpendicular line that goes through (-2,1) is:

substituting the values m = -2 and the point (-2,1)

Add 1 to both sides

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

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