Someone please please helppp... I need to submit this ttoday..I will mark you the brainliest

Problem 3

I'm not sure what your teacher is asking here. Identities are equations, but your teacher didn't give you an equation.

Problem 4

To show that we have an identity, I'm only going to manipulate the left hand side to transform it into the right hand side. The right hand side will remain the same the entire time.

(3x+7)^2 - 84x = (3x-7)^2

(3x+7)(3x+7) - 84x = (3x-7)^2

(9x^2+21x+21x+49) - 84x = (3x-7)^2

9x^2+42x+49-84x = (3x-7)^2

9x^2-42x+49 = (3x-7)^2

(3x-7)^2 = (3x-7)^2

The two formulas

may be handy in terms of expanding out (3x+7)^2 and factoring 9x^2-42x+49

Problem 5

x + 1/x = 11

a + b = 11 where a = x and b = 1/x

(a+b)^2 = 11^2

a^2 + 2ab + b^2 = 121

x^2 + 2*x*(1/x) + (1/x)^2 = 121

x^2 + 2 + 1/(x^2) = 121

x^2 + 1/(x^2) = 121-2

x^2 + 1/(x^2) = 119

An alternative route is to solve x + 1/x = 11 for x. You'll get two solutions. Use either solution to plug into x^2 + 1/(x^2) to find the result is 119.

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation: