Can someone please explain how I am supposed to do this I do not understand at all whatsoever.

B. (6,-3)

Step-by-step explanation:

3x - 5y ≥ 10

(1,4) IS NOT a solution to the equation

3(1) - 5(4) ≥ 10

3 - 20 ≥ 10

- 17 ≥ 10

3x - 5y ≥ 10

(6,-3) IS a solution to the equation

3(6) - 5(-3) ≥ 10

18 + 15 ≥ 10

33 ≥ 10

3x - 5y ≥ 10

(-5,-2) IS NOT a solution

3(-5) - 5(-2) ≥ 10

-15 + 10 ≥ 10

-5 ≥ 10

3x - 5y ≥ 10

(2,0) IS NOT solution

3x - 5y ≥ 10

3(2) - 5(0) ≥ 10

6 - 0 ≥ 10

6 ≥ 10

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

include a picture of the drawing in order for me to

step-by-step explanation: