![3x^4y^3- 48y^3= 3y^3(x^4 – 16)= 3y^3[(x^2)^2 - 4^2]= 3y^3(x^2 + 4)(x^2 - 4)= 3y^3(x^2 + 4)(x^2 - 2^2)= 3y^3(x^2 + 4)(x + 2)(x -2)](/tpl/images/0932/2816/16a64.png)
Factor: 3x4y3 – 48y3.
Solution:
3x4y3– 48y3.
= 3y3(x4 – 16).
=...
Mathematics, 29.11.2020 14:00 bridgettebach
Factor: 3x4y3 – 48y3.
Solution:
3x4y3– 48y3.
= 3y3(x4 – 16).
= 3y3[(x2)2 - 42].
= 3y3(x2 + 4)(x2 - 4).
= 3y3(x2 + 4)(x2 - 22).
= 3y3(x2 + 4)(x + 2)(x -2).
whats the answer?
Answers: 2
Another question on Mathematics
Mathematics, 21.06.2019 18:00
Based on the graph, what is the initial value of the linear relationship? a coordinate plane is shown. a line passes through the y-axis at -2 and the x-axis at 3.
Answers: 3
Mathematics, 21.06.2019 20:00
Parabolas y=−2x^2 and y=2x^2 +k intersect at points a and b that are in the third and the fourth quadrants respectively. find k if length of the segment ab is 5.
Answers: 1
Mathematics, 21.06.2019 20:00
In one day there are too high tides into low tides and equally spaced intervals the high tide is observed to be 6 feet above the average sea level after six hours passed a low tide occurs at 6 feet below the average sea level in this task you will model this occurrence using a trigonometric function by using x as a measurement of time assume the first high tide occurs at x=0. a. what are the independent and dependent variables? b. determine these key features of the function that models the tide: 1.amplitude 2.period 3.frequency 4.midline 5.vertical shift 6.phase shift c. create a trigonometric function that models the ocean tide for a period of 12 hours. d.what is the height of the tide after 93 hours?
Answers: 1
You know the right answer?
Questions
Mathematics, 25.11.2019 01:31
Mathematics, 25.11.2019 01:31
Mathematics, 25.11.2019 01:31
History, 25.11.2019 01:31
Mathematics, 25.11.2019 01:31
English, 25.11.2019 01:31
Mathematics, 25.11.2019 01:31
Mathematics, 25.11.2019 01:31
