Mathematics, 29.11.2020 18:30 funguy9198

Household incomes in a certain region are skewed right with mean $57,550 and standard deviation $16,200. The probability that the mean of a random sample of 4400 household incomes would differ from the population mean by $500 or more is about:. (a) 0.12 (b) 0.09 (c) 0.04 (d) 0.21 (e) 0.18

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Household incomes in a certain region are skewed right with mean $57,550 and standard deviation $16,...

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