Find m∠MON
I have a hard time with theses

m∠MON = 15°

Step-by-step explanation:

The given parameters are;

m∠LON = 77°

m∠LOM = 9·x + 44°

m∠MON = 6·x + 3°

By angle addition postulate, we have;

m∠LON = m∠LOM + m∠MON

Therefore, by substituting the known values, we have;

∴ 77° = 9·x + 44° + 6·x + 3°

77° = 9·x + 44° + 6·x + 3° = 15·x + 47°

77° = 15·x + 47°

77° - 47° = 15·x

15·x = 77° - 47° = 30°

15·x = 30°

x = 30°/15 = 2°

x = 2°

Given that m∠MON = 6·x + 3° and x = 2°, we have;

m∠MON = 6 × 2° + 3° = 12° + 3° = 15°

m∠MON = 15°.

a = 11 : 4

b = 38

c = 1 for every 6

fahrenheit

step-by-step explanation:

fahrenheit is more precise than celsius. the ambient temperature on most of the inhabited world ranges from -20 degrees fahrenheit to 110 degrees fahrenheit—a 130-degree range. on the celsius scale, that range is from -28.8 degrees to 43.3 degrees—a 72.1-degree range. this means that you can get a more exact measurement of the air temperature using fahrenheit because it uses almost twice the scale.