Let h be a differentiable function, and let f be the function defined by f(x) = h(x^2 - 3). Which of the following is equal to f′(2)? h'(1)

4h'(1)

4h'(2)

h'(4)

4h'(4)

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

answer: its c because when it has a magnet next to it it will move away from the mixture. hope this

step-by-step explanation: