Which statements are TRUE? Select all that apply. A. Marisa drives 112 miles in 1 hour and 45 minutes, which means her speed is 64 miles per hour.
B. If 6 pens cost $7.74, then 7 pens cost $9.03.
C. If Raymond drives at a speed of 57 miles per hour, then it takes him 4 hours and 10 minutes to drive 256.5 miles.
D. If 17 identical cans of soup cost $38.59, then 3 of the cans must cost $6.81.
E. Mr. Mayes buys two dozen eggs for $8.40, which means that he pays 70 cents per egg.

A, B, D are true

Step-by-step explanation:

A)  Speed = Distance travelled ÷ time taken

                 = 112 ÷ 1.75

                  = 64 miles per hour

True

B) Cost of 6 pens = $7.74

   Cost of 1 pen    = 7.74 ÷ 6 = $ 1.29

   Cost of 7 pens = 1.29 * 7   = $ 9.03

TRUE

C) Speed = 57 miles per hour

4 hour 10 minutes = 250 minutes

Distance traveled in an hour  = 57

Distance traveled in 250 minutes = (57* 250)   ÷ 60 = 237.50 miles

FALSE

D) Cost of 17 cans = $ 38.59

   Cost of 1 can      = 38.59 ÷ 17 = $2.27

   Cost of 3 cans    = 2.27 * 3 = $ 6.81

TRUE

e) Cost of two dozen eggs = $ 8.40

    Cost of an egg                = 8.40 ÷  24  =   $ 0.35

FALSE

4.6875 pounds

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.