Please help. will give brainliest The system of equations is shown in the graph.

2x + y = 4,

x – y = 2

What is the solution of the system?

(
,
)

(2,0)

Step-by-step explanation:

I will solve your system by substitution.

(You can also solve this system by elimination.)

2x+y=4; x−y=2

Step: Solve 2x+y = 4 for y:

2x + y + −2x = 4 + −2x (Add -2x to both sides)

y = −2x+4

Step: Substitute −2x+4 for y in x−y=2:

x − y=2

x−(−2x + 4)=2

3x − 4=2(Simplify both sides of the equation)

3x − 4 + 4 = 2+4 (Add 4 to both sides)

3x =6

(Divide both sides by 3)

x=2

Step: Substitute2forxiny=−2x+4:

y= −2x + 4

y=(−2)(2) + 4

y=0 (Simplify both sides of the equation)

x=2 and y=0

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2