3radical din 7 minus radical din 7 minus 2radical din 7 plus radical din 8 minus 5 radical din 7 minus 3 radical din 2

=  -5√7 -(√2)

Step-by-step explanation:

3√7- √7 -2√7+√8 -5√7-3√2

=3√7- √7 -2√7 -5√7+√8 -3√2   (first we place similar radicands together)

=-5√7+√8 -3√2                     ( solve the similar radicands)

=-5√7+√2³ -3 (2^1/2)          ( break 8 into powers of 2)

=-5√7+ (2)^3/2  -3 (2^1/2)        (solve 2 power with the radical sign)

=  -5√7+(2^1/2){ 2-3}             ( taking2^1/2 as common)

=  -5√7+(2^1/2){ -1}                  ( solving the co - efficients of 2^1/2)

=  -5√7 -1 (2^1/2)  

=  -5√7 -(√2)          {answer}

step-by-step explanation:

the triangles are similar. therefore the corresponding sides are in proportion:

              cross multiply

            divide both sides by 32