Graph f(x)=3/2x+2. plz help

draw a line trough (2,3) and (0, 2)

Step-by-step explanation:

f(x)=(3/2)x+2

so 3/2 is your slope  and 2 is your y coordinate of y-intercept

pick any point to start for example (0, 0) and go slope=rise/run=3/2 and you will end-up at (2,3)

now you have a point (2,3) and a second the y-intercept (0,2)

draw a line trough those points

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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step-by-step explanation: