Is there a series of rigid transformations that could map AQRS to AABC? If so, which transformations could be
used?
O No, AQRS and AABC are congruent but
AQRS cannot be mapped to AABC using a series
rigid transformations.
O No, AQRS and AABC are not congruent.
O Yes, AQRS can be translated so that Ris mapped to
B and then rotated so that S is mapped to C.
O Yes, AQRS can be translated so that Q is mapped to
A and then reflected across the line containing QS.

the answer is a if my teacher taught me correct

c. 6tan80

step-by-step explanation:

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²