Which point could be removed in order to make the relation a function? {(0, 2), (3, 8), (–4, –2), (3, –6), (–1, 8), (8, 3)}

(8, 3)
(3, –6)
(–1, 8)
(–4, –2)

(3, –6)

Step-by-step explanation:

A function is a relation where one input is assigned to exactly one output.

This means that no inputs must be repeated in the relation.

(0, 2), (3, 8), (–4, –2), (3, –6), (–1, 8), (8, 3)

The input of '3' repeats in the relation.

By removing (3, -6), we can make the relation given a function.

Hope this helps.

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

ιт ιѕ 6/23

step-by-step explanation:

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