Find the equation of the line that has a slope of 2 and passes through the point (5, -8). Write the
equation in point-slope form.

The equation in the point-slope form will be:

Step-by-step explanation:

The point-slope form of an equation is written as:

where m is the slope, and (x₁, y₁) is a point on the line.

Now, we will substitute the values of m and (x1, y1) in the given equation. Here,

m=2

and

(x1, y1) = (5, -8)

x1 = 5

y1 = -8

Therefore, the equation in the point-slope form will be:

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step-by-step explanation:

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δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)