Q1: 12 5/20 + 1 11/20 + 6 2/20
Q2: 9 5/10 x 5/8
Q3: 7x 10 3/7

199÷10=19.9, 95/26, 73

Step-by-step explanation:

=(12×20+5)÷20+(20×1+11)÷20+(6×20+2)÷20

=245÷20+31÷20+122÷20

=(245+31+122)÷20

=(276+122)÷20

=398÷20

=199÷10

=19.9

9 5/10×5/8

=(10×9+5)/10×5/8

=95×5/(10×8)

=475/80

=95/26

7×10 3/7

7×(7×10+3)/7

7×73/7

73

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation:

14

step-by-step explanation:

14